Base | Representation |
---|---|
bin | 10110110010010001111001… |
… | …001111101011000111100111 |
3 | 111010211012020021221110212221 |
4 | 112302101321033223013213 |
5 | 101113334102020232213 |
6 | 553044504303053211 |
7 | 30052044003560245 |
oct | 2662217117530747 |
9 | 433735207843787 |
10 | 100212211102183 |
11 | 29a2683a705164 |
12 | b2a596a8a1207 |
13 | 43bbc8127036b |
14 | 1aa6422983795 |
15 | b8bb39cb338d |
hex | 5b24793eb1e7 |
100212211102183 has 2 divisors, whose sum is σ = 100212211102184. Its totient is φ = 100212211102182.
The previous prime is 100212211102177. The next prime is 100212211102259. The reversal of 100212211102183 is 381201112212001.
It is a weak prime.
It is an emirp because it is prime and its reverse (381201112212001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100212211102183 - 25 = 100212211102151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100212211102163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50106105551091 + 50106105551092.
It is an arithmetic number, because the mean of its divisors is an integer number (50106105551092).
Almost surely, 2100212211102183 is an apocalyptic number.
100212211102183 is a deficient number, since it is larger than the sum of its proper divisors (1).
100212211102183 is an equidigital number, since it uses as much as digits as its factorization.
100212211102183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 25.
Adding to 100212211102183 its reverse (381201112212001), we get a palindrome (481413323314184).
The spelling of 100212211102183 in words is "one hundred trillion, two hundred twelve billion, two hundred eleven million, one hundred two thousand, one hundred eighty-three".
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