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100212240431 is a prime number
BaseRepresentation
bin101110101010100011…
…1010111000000101111
3100120122222000021101102
41131111013113000233
53120213313143211
6114011544033315
710145231663162
oct1352507270057
9316588007342
10100212240431
1139555219516
1217508a6283b
1395b07912b4
144bc930bad9
152917bb0a3b
hex17551d702f

100212240431 has 2 divisors, whose sum is σ = 100212240432. Its totient is φ = 100212240430.

The previous prime is 100212240397. The next prime is 100212240439. The reversal of 100212240431 is 134042212001.

It is a strong prime.

It is an emirp because it is prime and its reverse (134042212001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100212240431 is a prime.

It is a super-2 number, since 2×1002122404312 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100212240439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50106120215 + 50106120216.

It is an arithmetic number, because the mean of its divisors is an integer number (50106120216).

Almost surely, 2100212240431 is an apocalyptic number.

100212240431 is a deficient number, since it is larger than the sum of its proper divisors (1).

100212240431 is an equidigital number, since it uses as much as digits as its factorization.

100212240431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 100212240431 its reverse (134042212001), we get a palindrome (234254452432).

The spelling of 100212240431 in words is "one hundred billion, two hundred twelve million, two hundred forty thousand, four hundred thirty-one".