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100212333131 = 316931622699
BaseRepresentation
bin101110101010100011…
…1101101101001001011
3100120122222011222112202
41131111013231221023
53120213324130011
6114011550030415
710145232530351
oct1352507555113
9316588158482
10100212333131
1139555282129
1217508aa840b
1395b07c4551
144bc93337d1
152917bcd23b
hex17551eda4b

100212333131 has 4 divisors (see below), whose sum is σ = 100243959000. Its totient is φ = 100180707264.

The previous prime is 100212333121. The next prime is 100212333163. The reversal of 100212333131 is 131333212001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100212333131 is a prime.

It is a super-2 number, since 2×1002123331312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100212333101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15808181 + ... + 15814518.

It is an arithmetic number, because the mean of its divisors is an integer number (25060989750).

Almost surely, 2100212333131 is an apocalyptic number.

100212333131 is a deficient number, since it is larger than the sum of its proper divisors (31625869).

100212333131 is an equidigital number, since it uses as much as digits as its factorization.

100212333131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31625868.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 100212333131 its reverse (131333212001), we get a palindrome (231545545132).

The spelling of 100212333131 in words is "one hundred billion, two hundred twelve million, three hundred thirty-three thousand, one hundred thirty-one".

Divisors: 1 3169 31622699 100212333131