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1002133001251 is a prime number
BaseRepresentation
bin11101001010100111100…
…10000001010000100011
310112210200101001010010101
432211103302001100203
5112404332022020001
62044212404043231
7132254534651404
oct16452362012043
93483611033111
101002133001251
11357002a54348
12142278393517
137366816c765
14367098439ab
151b103b4ba01
hexe953c81423

1002133001251 has 2 divisors, whose sum is σ = 1002133001252. Its totient is φ = 1002133001250.

The previous prime is 1002133001179. The next prime is 1002133001267. The reversal of 1002133001251 is 1521003312001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1002133001251 - 27 = 1002133001123 is a prime.

It is a super-3 number, since 3×10021330012513 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1002133001851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501066500625 + 501066500626.

It is an arithmetic number, because the mean of its divisors is an integer number (501066500626).

Almost surely, 21002133001251 is an apocalyptic number.

1002133001251 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002133001251 is an equidigital number, since it uses as much as digits as its factorization.

1002133001251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 19.

Adding to 1002133001251 its reverse (1521003312001), we get a palindrome (2523136313252).

The spelling of 1002133001251 in words is "one trillion, two billion, one hundred thirty-three million, one thousand, two hundred fifty-one".