Base | Representation |
---|---|
bin | 10010101010101001… |
… | …01001111000111011 |
3 | 221212102001111102122 |
4 | 21111110221320323 |
5 | 131010440144121 |
6 | 4334225351455 |
7 | 503224412543 |
oct | 112524517073 |
9 | 27772044378 |
10 | 10021412411 |
11 | 428290a51a |
12 | 1b3819858b |
13 | c3927673a |
14 | 6b0d38323 |
15 | 3d9bdc5ab |
hex | 255529e3b |
10021412411 has 2 divisors, whose sum is σ = 10021412412. Its totient is φ = 10021412410.
The previous prime is 10021412381. The next prime is 10021412417. The reversal of 10021412411 is 11421412001.
It is a strong prime.
It is an emirp because it is prime and its reverse (11421412001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10021412411 - 214 = 10021396027 is a prime.
It is a super-2 number, since 2×100214124112 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 10021412411.
It is not a weakly prime, because it can be changed into another prime (10021412417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5010706205 + 5010706206.
It is an arithmetic number, because the mean of its divisors is an integer number (5010706206).
Almost surely, 210021412411 is an apocalyptic number.
10021412411 is a deficient number, since it is larger than the sum of its proper divisors (1).
10021412411 is an equidigital number, since it uses as much as digits as its factorization.
10021412411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 10021412411 its reverse (11421412001), we get a palindrome (21442824412).
The spelling of 10021412411 in words is "ten billion, twenty-one million, four hundred twelve thousand, four hundred eleven".
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