Base | Representation |
---|---|
bin | 11101001010101111101… |
… | …10001011010111110001 |
3 | 10112210212010100222101011 |
4 | 32211113312023113301 |
5 | 112410002001400423 |
6 | 2044223241510521 |
7 | 132256323434041 |
oct | 16452766132761 |
9 | 3483763328334 |
10 | 1002201200113 |
11 | 3570384a5143 |
12 | 1422971a2441 |
13 | 7367932a509 |
14 | 36714917721 |
15 | 1b109b1db0d |
hex | e957d8b5f1 |
1002201200113 has 8 divisors (see below), whose sum is σ = 1006047459648. Its totient is φ = 998355210864.
The previous prime is 1002201200087. The next prime is 1002201200167. The reversal of 1002201200113 is 3110021022001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1002201200113 - 25 = 1002201200081 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1002201200093 and 1002201200102.
It is not an unprimeable number, because it can be changed into a prime (1002201200173) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10547131 + ... + 10641727.
It is an arithmetic number, because the mean of its divisors is an integer number (125755932456).
Almost surely, 21002201200113 is an apocalyptic number.
It is an amenable number.
1002201200113 is a deficient number, since it is larger than the sum of its proper divisors (3846259535).
1002201200113 is an equidigital number, since it uses as much as digits as its factorization.
1002201200113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135143.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 1002201200113 its reverse (3110021022001), we get a palindrome (4112222222114).
The spelling of 1002201200113 in words is "one trillion, two billion, two hundred one million, two hundred thousand, one hundred thirteen".
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