Base | Representation |
---|---|
bin | 11101001010101111110… |
… | …01111111110001111011 |
3 | 10112210212012020211121212 |
4 | 32211113321333301323 |
5 | 112410002230414321 |
6 | 2044223315153335 |
7 | 132256335103511 |
oct | 16452771776173 |
9 | 3483765224555 |
10 | 1002202201211 |
11 | 3570390192a2 |
12 | 1422975a584b |
13 | 736795bb093 |
14 | 36714ad84b1 |
15 | 1b109c6a55b |
hex | e957e7fc7b |
1002202201211 has 2 divisors, whose sum is σ = 1002202201212. Its totient is φ = 1002202201210.
The previous prime is 1002202201193. The next prime is 1002202201213. The reversal of 1002202201211 is 1121022022001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1002202201211 - 226 = 1002135092347 is a prime.
It is a super-2 number, since 2×10022022012112 (a number of 25 digits) contains 22 as substring.
Together with 1002202201213, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1002202201213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501101100605 + 501101100606.
It is an arithmetic number, because the mean of its divisors is an integer number (501101100606).
Almost surely, 21002202201211 is an apocalyptic number.
1002202201211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002202201211 is an equidigital number, since it uses as much as digits as its factorization.
1002202201211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 1002202201211 its reverse (1121022022001), we get a palindrome (2123224223212).
The spelling of 1002202201211 in words is "one trillion, two billion, two hundred two million, two hundred one thousand, two hundred eleven".
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