Base | Representation |
---|---|
bin | 11101001010110000111… |
… | …00000001011111110111 |
3 | 10112210212211001000110201 |
4 | 32211120130001133313 |
5 | 112410012021334033 |
6 | 2044224234301331 |
7 | 132256503654241 |
oct | 16453034013767 |
9 | 3483784030421 |
10 | 1002211121143 |
11 | 357043060a41 |
12 | 14229a587847 |
13 | 7367b3c214b |
14 | 36715d7b091 |
15 | 1b10a92d47d |
hex | e9587017f7 |
1002211121143 has 2 divisors, whose sum is σ = 1002211121144. Its totient is φ = 1002211121142.
The previous prime is 1002211121113. The next prime is 1002211121147. The reversal of 1002211121143 is 3411211122001.
It is a strong prime.
It is an emirp because it is prime and its reverse (3411211122001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1002211121143 - 213 = 1002211112951 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1002211121143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1002211121147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501105560571 + 501105560572.
It is an arithmetic number, because the mean of its divisors is an integer number (501105560572).
Almost surely, 21002211121143 is an apocalyptic number.
1002211121143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002211121143 is an equidigital number, since it uses as much as digits as its factorization.
1002211121143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 1002211121143 its reverse (3411211122001), we get a palindrome (4413422243144).
The spelling of 1002211121143 in words is "one trillion, two billion, two hundred eleven million, one hundred twenty-one thousand, one hundred forty-three".
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