10022120113 has 4 divisors (see below), whose sum is σ = 10022771520. Its totient is φ = 10021468708.

The previous prime is 10022120093. The next prime is 10022120117. The reversal of 10022120113 is 31102122001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31102122001 = 97 ⋅320640433.

It is a cyclic number.

It is not a de Polignac number, because 10022120113 - 2⁵ = 10022120081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10022120093 and 10022120102.

It is not an unprimeable number, because it can be changed into a prime (10022120117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302053 + ... + 333586.

It is an arithmetic number, because the mean of its divisors is an integer number (2505692880).

Almost surely, 2^10022120113 is an apocalyptic number.

It is an amenable number.

10022120113 is a deficient number, since it is larger than the sum of its proper divisors (651407).

10022120113 is an equidigital number, since it uses as much as digits as its factorization.

10022120113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 651406.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10022120113 its reverse (31102122001), we get a palindrome (41124242114).

The spelling of 10022120113 in words is "ten billion, twenty-two million, one hundred twenty thousand, one hundred thirteen".