Base | Representation |
---|---|
bin | 1001000111010111010011… |
… | …1111001001101100011111 |
3 | 1022111002211212120111012001 |
4 | 2101311310333021230133 |
5 | 2303200301040212112 |
6 | 33152033215423131 |
7 | 2053034340302035 |
oct | 221656477115437 |
9 | 38432755514161 |
10 | 10022121413407 |
11 | 32143a3297364 |
12 | 115a430224aa7 |
13 | 57910b1aa85c |
14 | 269105076555 |
15 | 125a72055c57 |
hex | 91d74fc9b1f |
10022121413407 has 2 divisors, whose sum is σ = 10022121413408. Its totient is φ = 10022121413406.
The previous prime is 10022121413323. The next prime is 10022121413419. The reversal of 10022121413407 is 70431412122001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10022121413407 - 219 = 10022120889119 is a prime.
It is a super-2 number, since 2×100221214134072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10022121413207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011060706703 + 5011060706704.
It is an arithmetic number, because the mean of its divisors is an integer number (5011060706704).
Almost surely, 210022121413407 is an apocalyptic number.
10022121413407 is a deficient number, since it is larger than the sum of its proper divisors (1).
10022121413407 is an equidigital number, since it uses as much as digits as its factorization.
10022121413407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 10022121413407 its reverse (70431412122001), we get a palindrome (80453533535408).
The spelling of 10022121413407 in words is "ten trillion, twenty-two billion, one hundred twenty-one million, four hundred thirteen thousand, four hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •