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10022132017 is a prime number
BaseRepresentation
bin10010101010101110…
…11001100100110001
3221212110102001112201
421111113121210301
5131011131211032
64334253023201
7503233500532
oct112527314461
927773361481
1010022132017
114283261137
121b38484b01
13c39469141
146b1084689
153d9cd08e7
hex2555d9931

10022132017 has 2 divisors, whose sum is σ = 10022132018. Its totient is φ = 10022132016.

The previous prime is 10022131993. The next prime is 10022132023. The reversal of 10022132017 is 71023122001.

10022132017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7668329761 + 2353802256 = 87569^2 + 48516^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10022132017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10022131985 and 10022132003.

It is not a weakly prime, because it can be changed into another prime (10022132117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011066008 + 5011066009.

It is an arithmetic number, because the mean of its divisors is an integer number (5011066009).

Almost surely, 210022132017 is an apocalyptic number.

It is an amenable number.

10022132017 is a deficient number, since it is larger than the sum of its proper divisors (1).

10022132017 is an equidigital number, since it uses as much as digits as its factorization.

10022132017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168, while the sum is 19.

Adding to 10022132017 its reverse (71023122001), we get a palindrome (81045254018).

The spelling of 10022132017 in words is "ten billion, twenty-two million, one hundred thirty-two thousand, seventeen".