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100222131001 = 199503628799
BaseRepresentation
bin101110101010110110…
…1000101101100111001
3100120200122121202200211
41131111231011230321
53120223331143001
6114012540031121
710145412025516
oct1352555055471
9316618552624
10100222131001
113955a864443
12175102324a1
1395b28450c5
144bca76430d
1529189b6351
hex1755b45b39

100222131001 has 4 divisors (see below), whose sum is σ = 100725760000. Its totient is φ = 99718502004.

The previous prime is 100222130999. The next prime is 100222131013. The reversal of 100222131001 is 100131222001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100131222001 = 127487785423.

It is a cyclic number.

It is not a de Polignac number, because 100222131001 - 21 = 100222130999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100222132001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 251814201 + ... + 251814598.

It is an arithmetic number, because the mean of its divisors is an integer number (25181440000).

Almost surely, 2100222131001 is an apocalyptic number.

It is an amenable number.

100222131001 is a deficient number, since it is larger than the sum of its proper divisors (503628999).

100222131001 is an equidigital number, since it uses as much as digits as its factorization.

100222131001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 503628998.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 100222131001 its reverse (100131222001), we get a palindrome (200353353002).

The spelling of 100222131001 in words is "one hundred billion, two hundred twenty-two million, one hundred thirty-one thousand, one".

Divisors: 1 199 503628799 100222131001