100230055117 has 2 divisors, whose sum is σ = 100230055118. Its totient is φ = 100230055116.

The previous prime is 100230055097. The next prime is 100230055127. The reversal of 100230055117 is 711550032001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89672698116 + 10557357001 = 299454^2 + 102749^2 .

It is a cyclic number.

It is not a de Polignac number, because 100230055117 - 2²³ = 100221666509 is a prime.

It is a super-3 number, since 3×100230055117³ (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 100230055091 and 100230055100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100230055127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50115027558 + 50115027559.

It is an arithmetic number, because the mean of its divisors is an integer number (50115027559).

Almost surely, 2^100230055117 is an apocalyptic number.

It is an amenable number.

100230055117 is a deficient number, since it is larger than the sum of its proper divisors (1).

100230055117 is an equidigital number, since it uses as much as digits as its factorization.

100230055117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1050, while the sum is 25.

Adding to 100230055117 its reverse (711550032001), we get a palindrome (811780087118).

The spelling of 100230055117 in words is "one hundred billion, two hundred thirty million, fifty-five thousand, one hundred seventeen".