Base | Representation |
---|---|
bin | 1001000111011011000100… |
… | …0110101111111010111111 |
3 | 1022111012110011110220221122 |
4 | 2101312301012233322333 |
5 | 2303204332242203301 |
6 | 33152321250021155 |
7 | 2053101335413262 |
oct | 221666106577277 |
9 | 38435404426848 |
10 | 10023130037951 |
11 | 3214870670968 |
12 | 115a671b777bb |
13 | 57923c147504 |
14 | 26919cdcacd9 |
15 | 125ad088c81b |
hex | 91db11afebf |
10023130037951 has 2 divisors, whose sum is σ = 10023130037952. Its totient is φ = 10023130037950.
The previous prime is 10023130037923. The next prime is 10023130038011. The reversal of 10023130037951 is 15973003132001.
It is a weak prime.
It is an emirp because it is prime and its reverse (15973003132001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10023130037951 - 242 = 5625083526847 is a prime.
It is a super-2 number, since 2×100231300379512 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10023130037251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011565018975 + 5011565018976.
It is an arithmetic number, because the mean of its divisors is an integer number (5011565018976).
Almost surely, 210023130037951 is an apocalyptic number.
10023130037951 is a deficient number, since it is larger than the sum of its proper divisors (1).
10023130037951 is an equidigital number, since it uses as much as digits as its factorization.
10023130037951 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17010, while the sum is 35.
Adding to 10023130037951 its reverse (15973003132001), we get a palindrome (25996133169952).
The spelling of 10023130037951 in words is "ten trillion, twenty-three billion, one hundred thirty million, thirty-seven thousand, nine hundred fifty-one".
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