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100231311127 is a prime number
BaseRepresentation
bin101110101011001000…
…0000110111100010111
3100120201021220011110111
41131112100012330113
53120233203424002
6114013504503451
710145553041653
oct1352620067427
9316637804414
10100231311127
1139564a64622
121751331ab87
1395b470a72c
144bcba73a63
1529196cb3d7
hex1756406f17

100231311127 has 2 divisors, whose sum is σ = 100231311128. Its totient is φ = 100231311126.

The previous prime is 100231311113. The next prime is 100231311151. The reversal of 100231311127 is 721113132001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100231311127 - 219 = 100230786839 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100231311098 and 100231311107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100231311157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50115655563 + 50115655564.

It is an arithmetic number, because the mean of its divisors is an integer number (50115655564).

Almost surely, 2100231311127 is an apocalyptic number.

100231311127 is a deficient number, since it is larger than the sum of its proper divisors (1).

100231311127 is an equidigital number, since it uses as much as digits as its factorization.

100231311127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 100231311127 its reverse (721113132001), we get a palindrome (821344443128).

The spelling of 100231311127 in words is "one hundred billion, two hundred thirty-one million, three hundred eleven thousand, one hundred twenty-seven".