Base | Representation |
---|---|
bin | 11101001010111101000… |
… | …01001101001101011011 |
3 | 10112211010221000021022212 |
4 | 32211132201031031123 |
5 | 112410214131040011 |
6 | 2044242321105335 |
7 | 132262153100366 |
oct | 16453641151533 |
9 | 3484127007285 |
10 | 1002313143131 |
11 | 357095703633 |
12 | 14230878824b |
13 | 736965930a1 |
14 | 367257370dd |
15 | 1b11488208b |
hex | e95e84d35b |
1002313143131 has 2 divisors, whose sum is σ = 1002313143132. Its totient is φ = 1002313143130.
The previous prime is 1002313143119. The next prime is 1002313143151. The reversal of 1002313143131 is 1313413132001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1002313143131 - 234 = 985133273947 is a prime.
It is a super-2 number, since 2×10023131431312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1002313143097 and 1002313143106.
It is not a weakly prime, because it can be changed into another prime (1002313143151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501156571565 + 501156571566.
It is an arithmetic number, because the mean of its divisors is an integer number (501156571566).
Almost surely, 21002313143131 is an apocalyptic number.
1002313143131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002313143131 is an equidigital number, since it uses as much as digits as its factorization.
1002313143131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1002313143131 its reverse (1313413132001), we get a palindrome (2315726275132).
The spelling of 1002313143131 in words is "one trillion, two billion, three hundred thirteen million, one hundred forty-three thousand, one hundred thirty-one".
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