1002314310433 has 2 divisors, whose sum is σ = 1002314310434. Its totient is φ = 1002314310432.

The previous prime is 1002314310379. The next prime is 1002314310451. The reversal of 1002314310433 is 3340134132001.

1002314310433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 911274524449 + 91039785984 = 954607^2 + 301728^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1002314310433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1002314310398 and 1002314310407.

It is not a weakly prime, because it can be changed into another prime (1002314310733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501157155216 + 501157155217.

It is an arithmetic number, because the mean of its divisors is an integer number (501157155217).

Almost surely, 2^{1002314310433} is an apocalyptic number.

It is an amenable number.

1002314310433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002314310433 is an equidigital number, since it uses as much as digits as its factorization.

1002314310433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1002314310433 its reverse (3340134132001), we get a palindrome (4342448442434).

The spelling of 1002314310433 in words is "one trillion, two billion, three hundred fourteen million, three hundred ten thousand, four hundred thirty-three".