3340134132001 has 8 divisors (see below), whose sum is σ = 3603341151144. Its totient is φ = 3084341395200.

The previous prime is 3340134131993. The next prime is 3340134132019. The reversal of 3340134132001 is 1002314310433.

It can be written as a sum of positive squares in 4 ways, for example, as 520488659601 + 2819645472400 = 721449^2 + 1679180^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3340134132001 - 2³ = 3340134131993 is a prime.

It is a super-2 number, since 2×3340134132001² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3340134132091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1853569650 + ... + 1853571451.

It is an arithmetic number, because the mean of its divisors is an integer number (450417643893).

Almost surely, 2^{3340134132001} is an apocalyptic number.

It is an amenable number.

3340134132001 is a deficient number, since it is larger than the sum of its proper divisors (263207019143).

3340134132001 is a wasteful number, since it uses less digits than its factorization.

3340134132001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3707141171.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 3340134132001 its reverse (1002314310433), we get a palindrome (4342448442434).

The spelling of 3340134132001 in words is "three trillion, three hundred forty billion, one hundred thirty-four million, one hundred thirty-two thousand, one".