Base | Representation |
---|---|
bin | 1001000111011011001001… |
… | …0011000110011111100011 |
3 | 1022111012111120010210220121 |
4 | 2101312302103012133203 |
5 | 2303204402403201342 |
6 | 33152323243021111 |
7 | 2053102000505224 |
oct | 221666223063743 |
9 | 38435446123817 |
10 | 10023150053347 |
11 | 32148809a1812 |
12 | 115a67880a797 |
13 | 579243334942 |
14 | 2691a191b24b |
15 | 125ad24e3067 |
hex | 91db24c67e3 |
10023150053347 has 2 divisors, whose sum is σ = 10023150053348. Its totient is φ = 10023150053346.
The previous prime is 10023150053299. The next prime is 10023150053351. The reversal of 10023150053347 is 74335005132001.
It is a strong prime.
It is an emirp because it is prime and its reverse (74335005132001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10023150053347 - 27 = 10023150053219 is a prime.
It is not a weakly prime, because it can be changed into another prime (10023150053747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011575026673 + 5011575026674.
It is an arithmetic number, because the mean of its divisors is an integer number (5011575026674).
Almost surely, 210023150053347 is an apocalyptic number.
10023150053347 is a deficient number, since it is larger than the sum of its proper divisors (1).
10023150053347 is an equidigital number, since it uses as much as digits as its factorization.
10023150053347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 37800, while the sum is 34.
Adding to 10023150053347 its reverse (74335005132001), we get a palindrome (84358155185348).
The spelling of 10023150053347 in words is "ten trillion, twenty-three billion, one hundred fifty million, fifty-three thousand, three hundred forty-seven".
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