100232111313001 has 4 divisors (see below), whose sum is σ = 100232150185552. Its totient is φ = 100232072440452.

The previous prime is 100232111312987. The next prime is 100232111313043. The reversal of 100232111313001 is 100313111232001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100232111313001 is a prime.

It is a super-2 number, since 2×100232111313001² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 100232111313001.

It is not an unprimeable number, because it can be changed into a prime (100232511313001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15271011 + ... + 20824696.

It is an arithmetic number, because the mean of its divisors is an integer number (25058037546388).

Almost surely, 2^{100232111313001} is an apocalyptic number.

It is an amenable number.

100232111313001 is a deficient number, since it is larger than the sum of its proper divisors (38872551).

100232111313001 is an equidigital number, since it uses as much as digits as its factorization.

100232111313001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38872550.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 100232111313001 its reverse (100313111232001), we get a palindrome (200545222545002).

The spelling of 100232111313001 in words is "one hundred trillion, two hundred thirty-two billion, one hundred eleven million, three hundred thirteen thousand, one".