Base | Representation |
---|---|
bin | 1001000111011100101011… |
… | …0111001001100001110011 |
3 | 1022111020120021120210200021 |
4 | 2101313022313021201303 |
5 | 2303211223402444042 |
6 | 33152432203504311 |
7 | 2053115133355141 |
oct | 221671267114163 |
9 | 38436507523607 |
10 | 10023562156147 |
11 | 3214a72583741 |
12 | 115a772828097 |
13 | 5792aa822c57 |
14 | 269200552591 |
15 | 125b08797867 |
hex | 91dcadc9873 |
10023562156147 has 2 divisors, whose sum is σ = 10023562156148. Its totient is φ = 10023562156146.
The previous prime is 10023562156129. The next prime is 10023562156199. The reversal of 10023562156147 is 74165126532001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10023562156147 is a prime.
It is not a weakly prime, because it can be changed into another prime (10023566156147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5011781078073 + 5011781078074.
It is an arithmetic number, because the mean of its divisors is an integer number (5011781078074).
Almost surely, 210023562156147 is an apocalyptic number.
10023562156147 is a deficient number, since it is larger than the sum of its proper divisors (1).
10023562156147 is an equidigital number, since it uses as much as digits as its factorization.
10023562156147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 302400, while the sum is 43.
Adding to 10023562156147 its reverse (74165126532001), we get a palindrome (84188688688148).
The spelling of 10023562156147 in words is "ten trillion, twenty-three billion, five hundred sixty-two million, one hundred fifty-six thousand, one hundred forty-seven".
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