Base | Representation |
---|---|
bin | 11101001011000111101… |
… | …01110110110010110111 |
3 | 10112211101011001010221001 |
4 | 32211203311312302313 |
5 | 112410410011124143 |
6 | 2044255231104131 |
7 | 132264316114234 |
oct | 16454365666267 |
9 | 3484334033831 |
10 | 1002402442423 |
11 | 3571310564a8 |
12 | 142332672047 |
13 | 736abc2b0c5 |
14 | 3673354078b |
15 | 1b11c62114d |
hex | e963d76cb7 |
1002402442423 has 2 divisors, whose sum is σ = 1002402442424. Its totient is φ = 1002402442422.
The previous prime is 1002402442267. The next prime is 1002402442507. The reversal of 1002402442423 is 3242442042001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1002402442423 - 225 = 1002368887991 is a prime.
It is a super-2 number, since 2×10024024424232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1002402442391 and 1002402442400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1002402442823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501201221211 + 501201221212.
It is an arithmetic number, because the mean of its divisors is an integer number (501201221212).
Almost surely, 21002402442423 is an apocalyptic number.
1002402442423 is a deficient number, since it is larger than the sum of its proper divisors (1).
1002402442423 is an equidigital number, since it uses as much as digits as its factorization.
1002402442423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12288, while the sum is 28.
Adding to 1002402442423 its reverse (3242442042001), we get a palindrome (4244844484424).
The spelling of 1002402442423 in words is "one trillion, two billion, four hundred two million, four hundred forty-two thousand, four hundred twenty-three".
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