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100242211997 is a prime number
BaseRepresentation
bin101110101011011100…
…1101100010010011101
3100120202001101222122102
41131112321230102131
53120244001240442
6114014534254445
710146044512634
oct1352671542235
9316661358572
10100242211997
113957012a604
1217516ab7425
1395b6a56355
144bcd2b051b
15291a631232
hex1756e6c49d

100242211997 has 2 divisors, whose sum is σ = 100242211998. Its totient is φ = 100242211996.

The previous prime is 100242211969. The next prime is 100242212009. The reversal of 100242211997 is 799112242001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99792178201 + 450033796 = 315899^2 + 21214^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100242211997 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 100242211997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100242211297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50121105998 + 50121105999.

It is an arithmetic number, because the mean of its divisors is an integer number (50121105999).

Almost surely, 2100242211997 is an apocalyptic number.

It is an amenable number.

100242211997 is a deficient number, since it is larger than the sum of its proper divisors (1).

100242211997 is an equidigital number, since it uses as much as digits as its factorization.

100242211997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18144, while the sum is 38.

Adding to 100242211997 its reverse (799112242001), we get a palindrome (899354453998).

The spelling of 100242211997 in words is "one hundred billion, two hundred forty-two million, two hundred eleven thousand, nine hundred ninety-seven".