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10024342117 is a prime number
BaseRepresentation
bin10010101010111111…
…10101001001100101
3221212121120100020021
421111133311021211
5131012212421432
64334412235141
7503261334136
oct112537651145
927777510207
1010024342117
114284530669
121b3916bab1
13c39a610aa
146b149bc8d
153da0ba697
hex2557f5265

10024342117 has 2 divisors, whose sum is σ = 10024342118. Its totient is φ = 10024342116.

The previous prime is 10024342099. The next prime is 10024342127. The reversal of 10024342117 is 71124342001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9999800001 + 24542116 = 99999^2 + 4954^2 .

It is a cyclic number.

It is not a de Polignac number, because 10024342117 - 27 = 10024341989 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10024342091 and 10024342100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10024342127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012171058 + 5012171059.

It is an arithmetic number, because the mean of its divisors is an integer number (5012171059).

Almost surely, 210024342117 is an apocalyptic number.

It is an amenable number.

10024342117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10024342117 is an equidigital number, since it uses as much as digits as its factorization.

10024342117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 10024342117 its reverse (71124342001), we get a palindrome (81148684118).

The spelling of 10024342117 in words is "ten billion, twenty-four million, three hundred forty-two thousand, one hundred seventeen".