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1002434214003 = 3232631653569
BaseRepresentation
bin11101001011001011011…
…11000011100001110011
310112211110100211022100020
432211211233003201303
5112410441124322003
62044302324054523
7132265153141605
oct16454557034163
93484410738306
101002434214003
11357147a86a02
12142341234443
13736b56a3561
1436737851175
151b1202e9d53
hexe965bc3873

1002434214003 has 12 divisors (see below), whose sum is σ = 1397217696840. Its totient is φ = 639233410816.

The previous prime is 1002434213993. The next prime is 1002434214043. The reversal of 1002434214003 is 3004124342001.

It is not a de Polignac number, because 1002434214003 - 25 = 1002434213971 is a prime.

It is a super-3 number, since 3×10024342140033 (a number of 37 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (1002434214043) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 315825198 + ... + 315828371.

It is an arithmetic number, because the mean of its divisors is an integer number (116434808070).

Almost surely, 21002434214003 is an apocalyptic number.

1002434214003 is a deficient number, since it is larger than the sum of its proper divisors (394783482837).

1002434214003 is an equidigital number, since it uses as much as digits as its factorization.

1002434214003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 631653618 (or 631653595 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 1002434214003 its reverse (3004124342001), we get a palindrome (4006558556004).

The spelling of 1002434214003 in words is "one trillion, two billion, four hundred thirty-four million, two hundred fourteen thousand, three".

Divisors: 1 3 23 69 529 1587 631653569 1894960707 14528032087 43584096261 334144738001 1002434214003