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10024430113 = 31531317923
BaseRepresentation
bin10010101011000000…
…01010101000100001
3221212121201210221101
421111200022220201
5131012223230423
64334414154401
7503262151525
oct112540125041
927777653841
1010024430113
114284590795
121b391b2a01
13c39a92169
146b14c1d85
153da0d67ad
hex25580aa21

10024430113 has 4 divisors (see below), whose sum is σ = 10024779568. Its totient is φ = 10024080660.

The previous prime is 10024430099. The next prime is 10024430189. The reversal of 10024430113 is 31103442001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31103442001 = 181171842221.

It is a cyclic number.

It is not a de Polignac number, because 10024430113 - 217 = 10024299041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10024410113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127431 + ... + 190492.

It is an arithmetic number, because the mean of its divisors is an integer number (2506194892).

Almost surely, 210024430113 is an apocalyptic number.

It is an amenable number.

10024430113 is a deficient number, since it is larger than the sum of its proper divisors (349455).

10024430113 is an equidigital number, since it uses as much as digits as its factorization.

10024430113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 349454.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 10024430113 its reverse (31103442001), we get a palindrome (41127872114).

The spelling of 10024430113 in words is "ten billion, twenty-four million, four hundred thirty thousand, one hundred thirteen".

Divisors: 1 31531 317923 10024430113