Base | Representation |
---|---|
bin | 10010101011000000… |
… | …01101100111101011 |
3 | 221212121202102201111 |
4 | 21111200031213223 |
5 | 131012224123342 |
6 | 4334414331151 |
7 | 503262232303 |
oct | 112540154753 |
9 | 27777672644 |
10 | 10024442347 |
11 | 42845999a7 |
12 | 1b391b9ab7 |
13 | c39a978ba |
14 | 6b14c6603 |
15 | 3da0da217 |
hex | 25580d9eb |
10024442347 has 2 divisors, whose sum is σ = 10024442348. Its totient is φ = 10024442346.
The previous prime is 10024442299. The next prime is 10024442357. The reversal of 10024442347 is 74324442001.
10024442347 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (74324442001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10024442347 - 231 = 7876958699 is a prime.
It is not a weakly prime, because it can be changed into another prime (10024442357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012221173 + 5012221174.
It is an arithmetic number, because the mean of its divisors is an integer number (5012221174).
Almost surely, 210024442347 is an apocalyptic number.
10024442347 is a deficient number, since it is larger than the sum of its proper divisors (1).
10024442347 is an equidigital number, since it uses as much as digits as its factorization.
10024442347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 31.
Adding to 10024442347 its reverse (74324442001), we get a palindrome (84348884348).
The spelling of 10024442347 in words is "ten billion, twenty-four million, four hundred forty-two thousand, three hundred forty-seven".
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