Base | Representation |
---|---|
bin | 1001000111100010100001… |
… | …1000100111110011101011 |
3 | 1022111101121122001002200102 |
4 | 2101320220120213303223 |
5 | 2303222432042241021 |
6 | 33153252014100015 |
7 | 2053202045205056 |
oct | 221705030476353 |
9 | 38441548032612 |
10 | 10025131212011 |
11 | 32156a823a623 |
12 | 115ab301aa60b |
13 | 57949a913086 |
14 | 26930caada9d |
15 | 125b9b3d300b |
hex | 91e28627ceb |
10025131212011 has 2 divisors, whose sum is σ = 10025131212012. Its totient is φ = 10025131212010.
The previous prime is 10025131211999. The next prime is 10025131212023. The reversal of 10025131212011 is 11021213152001.
10025131212011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (10025131211999) and next prime (10025131212023).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10025131212011 is a prime.
It is not a weakly prime, because it can be changed into another prime (10025131212071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5012565606005 + 5012565606006.
It is an arithmetic number, because the mean of its divisors is an integer number (5012565606006).
Almost surely, 210025131212011 is an apocalyptic number.
10025131212011 is a deficient number, since it is larger than the sum of its proper divisors (1).
10025131212011 is an equidigital number, since it uses as much as digits as its factorization.
10025131212011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 20.
Adding to 10025131212011 its reverse (11021213152001), we get a palindrome (21046344364012).
The spelling of 10025131212011 in words is "ten trillion, twenty-five billion, one hundred thirty-one million, two hundred twelve thousand, eleven".
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