1002540113 has 2 divisors, whose sum is σ = 1002540114. Its totient is φ = 1002540112.

The previous prime is 1002540109. The next prime is 1002540163. The reversal of 1002540113 is 3110452001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 987970624 + 14569489 = 31432^2 + 3817^2 .

It is a cyclic number.

It is not a de Polignac number, because 1002540113 - 2² = 1002540109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1002540091 and 1002540100.

It is not a weakly prime, because it can be changed into another prime (1002540163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501270056 + 501270057.

It is an arithmetic number, because the mean of its divisors is an integer number (501270057).

Almost surely, 2^1002540113 is an apocalyptic number.

It is an amenable number.

1002540113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1002540113 is an equidigital number, since it uses as much as digits as its factorization.

1002540113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 1002540113 is about 31662.9138425382. The cubic root of 1002540113 is about 1000.8459884351.

Adding to 1002540113 its reverse (3110452001), we get a palindrome (4112992114).

The spelling of 1002540113 in words is "one billion, two million, five hundred forty thousand, one hundred thirteen".