1003100113 has 4 divisors (see below), whose sum is σ = 1062106020. Its totient is φ = 944094208.

The previous prime is 1003100099. The next prime is 1003100129. The reversal of 1003100113 is 3110013001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3110013001 = 193 ⋅16114057.

It can be written as a sum of positive squares in 2 ways, for example, as 812991169 + 190108944 = 28513^2 + 13788^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1003100113 is a prime.

It is a super-2 number, since 2×1003100113² = 2012419673401225538, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1003100113.

It is not an unprimeable number, because it can be changed into a prime (1003100213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29502928 + ... + 29502961.

It is an arithmetic number, because the mean of its divisors is an integer number (265526505).

Almost surely, 2^1003100113 is an apocalyptic number.

It is an amenable number.

1003100113 is a deficient number, since it is larger than the sum of its proper divisors (59005907).

1003100113 is an equidigital number, since it uses as much as digits as its factorization.

1003100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59005906.

The product of its (nonzero) digits is 9, while the sum is 10.

The square root of 1003100113 is about 31671.7557612457. The cubic root of 1003100113 is about 1001.0323049797.

Adding to 1003100113 its reverse (3110013001), we get a palindrome (4113113114).

The spelling of 1003100113 in words is "one billion, three million, one hundred thousand, one hundred thirteen".