1003103031113 has 4 divisors (see below), whose sum is σ = 1005430416768. Its totient is φ = 1000775645460.

The previous prime is 1003103031109. The next prime is 1003103031127. The reversal of 1003103031113 is 3111303013001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1003103031113 - 2² = 1003103031109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1003103031091 and 1003103031100.

It is not an unprimeable number, because it can be changed into a prime (1003103031103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1163692181 + ... + 1163693042.

It is an arithmetic number, because the mean of its divisors is an integer number (251357604192).

Almost surely, 2^{1003103031113} is an apocalyptic number.

It is an amenable number.

1003103031113 is a deficient number, since it is larger than the sum of its proper divisors (2327385655).

1003103031113 is an equidigital number, since it uses as much as digits as its factorization.

1003103031113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2327385654.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1003103031113 its reverse (3111303013001), we get a palindrome (4114406044114).

The spelling of 1003103031113 in words is "one trillion, three billion, one hundred three million, thirty-one thousand, one hundred thirteen".