Base | Representation |
---|---|
bin | 11101001100011100010… |
… | …01000011101101000111 |
3 | 10112220012121102110022211 |
4 | 32212032021003231013 |
5 | 112413333200302421 |
6 | 2044453502004251 |
7 | 132321024220414 |
oct | 16461611035507 |
9 | 3486177373284 |
10 | 1003112119111 |
11 | 357465705063 |
12 | 1424b0276687 |
13 | 73792c77b3b |
14 | 3679d8b710b |
15 | 1b15eaa59e1 |
hex | e98e243b47 |
1003112119111 has 2 divisors, whose sum is σ = 1003112119112. Its totient is φ = 1003112119110.
The previous prime is 1003112119103. The next prime is 1003112119157. The reversal of 1003112119111 is 1119112113001.
1003112119111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (1119112113001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1003112119111 - 23 = 1003112119103 is a prime.
It is a super-2 number, since 2×10031121191112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1003112119171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501556059555 + 501556059556.
It is an arithmetic number, because the mean of its divisors is an integer number (501556059556).
Almost surely, 21003112119111 is an apocalyptic number.
1003112119111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1003112119111 is an equidigital number, since it uses as much as digits as its factorization.
1003112119111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 22.
The spelling of 1003112119111 in words is "one trillion, three billion, one hundred twelve million, one hundred nineteen thousand, one hundred eleven".
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