Base | Representation |
---|---|
bin | 101110101101100000… |
… | …1010101001010101111 |
3 | 100120220212110012112201 |
4 | 1131123001111022233 |
5 | 3120414144321221 |
6 | 114025443442331 |
7 | 10150544115433 |
oct | 1353301251257 |
9 | 316825405481 |
10 | 100311323311 |
11 | 395a61439a1 |
12 | 175360863a7 |
13 | 95c8173514 |
14 | 4bd85409c3 |
15 | 2921733891 |
hex | 175b0552af |
100311323311 has 4 divisors (see below), whose sum is σ = 100380362152. Its totient is φ = 100242284472.
The previous prime is 100311323291. The next prime is 100311323317. The reversal of 100311323311 is 113323113001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 100311323311 - 219 = 100310799023 is a prime.
It is a super-4 number, since 4×1003113233114 (a number of 45 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100311323317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34517241 + ... + 34520146.
It is an arithmetic number, because the mean of its divisors is an integer number (25095090538).
Almost surely, 2100311323311 is an apocalyptic number.
100311323311 is a deficient number, since it is larger than the sum of its proper divisors (69038841).
100311323311 is an equidigital number, since it uses as much as digits as its factorization.
100311323311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69038840.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 100311323311 its reverse (113323113001), we get a palindrome (213634436312).
The spelling of 100311323311 in words is "one hundred billion, three hundred eleven million, three hundred twenty-three thousand, three hundred eleven".
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