10031133113 has 2 divisors, whose sum is σ = 10031133114. Its totient is φ = 10031133112.

The previous prime is 10031133107. The next prime is 10031133121. The reversal of 10031133113 is 31133113001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5759595664 + 4271537449 = 75892^2 + 65357^2 .

It is a cyclic number.

It is not a de Polignac number, because 10031133113 - 2¹⁴ = 10031116729 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10031133091 and 10031133100.

It is not a weakly prime, because it can be changed into another prime (10031133193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5015566556 + 5015566557.

It is an arithmetic number, because the mean of its divisors is an integer number (5015566557).

Almost surely, 2^10031133113 is an apocalyptic number.

It is an amenable number.

10031133113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10031133113 is an equidigital number, since it uses as much as digits as its factorization.

10031133113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 10031133113 its reverse (31133113001), we get a palindrome (41164246114).

The spelling of 10031133113 in words is "ten billion, thirty-one million, one hundred thirty-three thousand, one hundred thirteen".