Base | Representation |
---|---|
bin | 10110110011101111001000… |
… | …111111001011101010101110 |
3 | 111011011202122222100020112102 |
4 | 112303233020333023222232 |
5 | 101122004124300013032 |
6 | 553202503311135102 |
7 | 30062220062443163 |
oct | 2663571077135256 |
9 | 434152588306472 |
10 | 100312333204142 |
11 | 29a65248a58274 |
12 | b301251514492 |
13 | 43c8549161687 |
14 | 1aab1ddd0a06a |
15 | b8e549abb362 |
hex | 5b3bc8fcbaae |
100312333204142 has 4 divisors (see below), whose sum is σ = 150468499806216. Its totient is φ = 50156166602070.
The previous prime is 100312333204141. The next prime is 100312333204199. The reversal of 100312333204142 is 241402333213001.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×1003123332041423 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100312333204141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25078083301034 + ... + 25078083301037.
It is an arithmetic number, because the mean of its divisors is an integer number (37617124951554).
Almost surely, 2100312333204142 is an apocalyptic number.
100312333204142 is a deficient number, since it is larger than the sum of its proper divisors (50156166602074).
100312333204142 is an equidigital number, since it uses as much as digits as its factorization.
100312333204142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50156166602073.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 100312333204142 its reverse (241402333213001), we get a palindrome (341714666417143).
The spelling of 100312333204142 in words is "one hundred trillion, three hundred twelve billion, three hundred thirty-three million, two hundred four thousand, one hundred forty-two".
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