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100313200241 is a prime number
BaseRepresentation
bin101110101101100100…
…0011111011001110001
3100120220222222120012122
41131123020133121301
53120420134401431
6114025552004025
710150566063512
oct1353310373161
9316828876178
10100313200241
11395a7206081
1217536830615
1395c867c927
144bd88aca09
1529219a4a7b
hex175b21f671

100313200241 has 2 divisors, whose sum is σ = 100313200242. Its totient is φ = 100313200240.

The previous prime is 100313200219. The next prime is 100313200249. The reversal of 100313200241 is 142002313001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 54718566400 + 45594633841 = 233920^2 + 213529^2 .

It is an emirp because it is prime and its reverse (142002313001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100313200241 is a prime.

It is not a weakly prime, because it can be changed into another prime (100313200249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50156600120 + 50156600121.

It is an arithmetic number, because the mean of its divisors is an integer number (50156600121).

Almost surely, 2100313200241 is an apocalyptic number.

It is an amenable number.

100313200241 is a deficient number, since it is larger than the sum of its proper divisors (1).

100313200241 is an equidigital number, since it uses as much as digits as its factorization.

100313200241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 100313200241 its reverse (142002313001), we get a palindrome (242315513242).

The spelling of 100313200241 in words is "one hundred billion, three hundred thirteen million, two hundred thousand, two hundred forty-one".