Base | Representation |
---|---|
bin | 1001000111111001100101… |
… | …1101101101110100000111 |
3 | 1022111222121011121210110112 |
4 | 2101332121131231310013 |
5 | 2303323122233340124 |
6 | 33200154252543235 |
7 | 2053511354343341 |
oct | 221763135556407 |
9 | 38458534553415 |
10 | 10031323340039 |
11 | 3218295567001 |
12 | 1160179a81b1b |
13 | 579c4673b061 |
14 | 269739212291 |
15 | 125e0ed1c90e |
hex | 91f9976dd07 |
10031323340039 has 2 divisors, whose sum is σ = 10031323340040. Its totient is φ = 10031323340038.
The previous prime is 10031323339951. The next prime is 10031323340063. The reversal of 10031323340039 is 93004332313001.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10031323340039 is a prime.
It is a super-2 number, since 2×100313233400392 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10031323339987 and 10031323340014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10031323340239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5015661670019 + 5015661670020.
It is an arithmetic number, because the mean of its divisors is an integer number (5015661670020).
Almost surely, 210031323340039 is an apocalyptic number.
10031323340039 is a deficient number, since it is larger than the sum of its proper divisors (1).
10031323340039 is an equidigital number, since it uses as much as digits as its factorization.
10031323340039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17496, while the sum is 32.
The spelling of 10031323340039 in words is "ten trillion, thirty-one billion, three hundred twenty-three million, three hundred forty thousand, thirty-nine".
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