Base | Representation |
---|---|
bin | 101110101101100101… |
… | …1100010101010101001 |
3 | 100120221001111012022212 |
4 | 1131123023202222221 |
5 | 3120420341000131 |
6 | 114030021054505 |
7 | 10150605634343 |
oct | 1353313425251 |
9 | 316831435285 |
10 | 100314000041 |
11 | 395a7701a72 |
12 | 17536b57435 |
13 | 95c889c998 |
14 | 4bd8a3a293 |
15 | 2921ab1a2b |
hex | 175b2e2aa9 |
100314000041 has 2 divisors, whose sum is σ = 100314000042. Its totient is φ = 100314000040.
The previous prime is 100314000013. The next prime is 100314000077. The reversal of 100314000041 is 140000413001.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 51982176016 + 48331824025 = 227996^2 + 219845^2 .
It is a cyclic number.
It is not a de Polignac number, because 100314000041 - 26 = 100313999977 is a prime.
It is not a weakly prime, because it can be changed into another prime (100314000091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50157000020 + 50157000021.
It is an arithmetic number, because the mean of its divisors is an integer number (50157000021).
Almost surely, 2100314000041 is an apocalyptic number.
It is an amenable number.
100314000041 is a deficient number, since it is larger than the sum of its proper divisors (1).
100314000041 is an equidigital number, since it uses as much as digits as its factorization.
100314000041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 100314000041 its reverse (140000413001), we get a palindrome (240314413042).
The spelling of 100314000041 in words is "one hundred billion, three hundred fourteen million, forty-one", and thus it is an aban number.
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