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10031424166339 is a prime number
BaseRepresentation
bin1001000111111001111101…
…1110010101100111000011
31022111222212012100022010221
42101332133132111213003
52303323324041310324
633200212254003511
72053514020346512
oct221763736254703
938458765308127
1010031424166339
113218337472324
1211601a77a6597
13579c615b09a4
1426974877a679
15125e18ad70e4
hex91f9f7959c3

10031424166339 has 2 divisors, whose sum is σ = 10031424166340. Its totient is φ = 10031424166338.

The previous prime is 10031424166333. The next prime is 10031424166409. The reversal of 10031424166339 is 93366142413001.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10031424166339 - 221 = 10031422069187 is a prime.

It is a super-2 number, since 2×100314241663392 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10031424166295 and 10031424166304.

It is not a weakly prime, because it can be changed into another prime (10031424166333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5015712083169 + 5015712083170.

It is an arithmetic number, because the mean of its divisors is an integer number (5015712083170).

Almost surely, 210031424166339 is an apocalyptic number.

10031424166339 is a deficient number, since it is larger than the sum of its proper divisors (1).

10031424166339 is an equidigital number, since it uses as much as digits as its factorization.

10031424166339 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 279936, while the sum is 43.

The spelling of 10031424166339 in words is "ten trillion, thirty-one billion, four hundred twenty-four million, one hundred sixty-six thousand, three hundred thirty-nine".