Base | Representation |
---|---|
bin | 101110101101100110… |
… | …0101111001011100001 |
3 | 100120221002002010020021 |
4 | 1131123030233023201 |
5 | 3120420431012231 |
6 | 114030031513441 |
7 | 10150611411136 |
oct | 1353314571341 |
9 | 316832063207 |
10 | 100314313441 |
11 | 395a78a6481 |
12 | 17537088881 |
13 | 95c897c524 |
14 | 4bd8abc58d |
15 | 2921b24811 |
hex | 175b32f2e1 |
100314313441 has 2 divisors, whose sum is σ = 100314313442. Its totient is φ = 100314313440.
The previous prime is 100314313423. The next prime is 100314313469. The reversal of 100314313441 is 144313413001.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72416962816 + 27897350625 = 269104^2 + 167025^2 .
It is a cyclic number.
It is not a de Polignac number, because 100314313441 - 25 = 100314313409 is a prime.
It is a super-2 number, since 2×1003143134412 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100314313481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50157156720 + 50157156721.
It is an arithmetic number, because the mean of its divisors is an integer number (50157156721).
Almost surely, 2100314313441 is an apocalyptic number.
It is an amenable number.
100314313441 is a deficient number, since it is larger than the sum of its proper divisors (1).
100314313441 is an equidigital number, since it uses as much as digits as its factorization.
100314313441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 100314313441 its reverse (144313413001), we get a palindrome (244627726442).
The spelling of 100314313441 in words is "one hundred billion, three hundred fourteen million, three hundred thirteen thousand, four hundred forty-one".
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