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100314331231 = 472134347473
BaseRepresentation
bin101110101101100110…
…0110011100001011111
3100120221002010000122011
41131123030303201133
53120420432044411
6114030032132051
710150611514042
oct1353314634137
9316832100564
10100314331231
11395a7908884
1217537097027
1395c898765a
144bd8ac4c59
152921b29c21
hex175b33385f

100314331231 has 4 divisors (see below), whose sum is σ = 102448678752. Its totient is φ = 98179983712.

The previous prime is 100314331207. The next prime is 100314331253. The reversal of 100314331231 is 132133413001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100314331231 - 25 = 100314331199 is a prime.

It is a super-2 number, since 2×1003143312312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100314331531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1067173690 + ... + 1067173783.

It is an arithmetic number, because the mean of its divisors is an integer number (25612169688).

Almost surely, 2100314331231 is an apocalyptic number.

100314331231 is a deficient number, since it is larger than the sum of its proper divisors (2134347521).

100314331231 is an equidigital number, since it uses as much as digits as its factorization.

100314331231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2134347520.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 100314331231 its reverse (132133413001), we get a palindrome (232447744232).

The spelling of 100314331231 in words is "one hundred billion, three hundred fourteen million, three hundred thirty-one thousand, two hundred thirty-one".

Divisors: 1 47 2134347473 100314331231