Base | Representation |
---|---|
bin | 10110110011110010110110… |
… | …010001011110011010011011 |
3 | 111011012010221102021202210121 |
4 | 112303302312101132122123 |
5 | 101122040302413342312 |
6 | 553204402321454111 |
7 | 30062420532365224 |
oct | 2663626621363233 |
9 | 434163842252717 |
10 | 100316314199707 |
11 | 29a66a01141151 |
12 | b301b827a1337 |
13 | 43c8a31b5ab58 |
14 | 1aab49a91424b |
15 | b8e6ce33a707 |
hex | 5b3cb645e69b |
100316314199707 has 2 divisors, whose sum is σ = 100316314199708. Its totient is φ = 100316314199706.
The previous prime is 100316314199701. The next prime is 100316314199713. The reversal of 100316314199707 is 707991413613001.
It is a balanced prime because it is at equal distance from previous prime (100316314199701) and next prime (100316314199713).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100316314199707 is a prime.
It is a super-2 number, since 2×1003163141997072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100316314199701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50158157099853 + 50158157099854.
It is an arithmetic number, because the mean of its divisors is an integer number (50158157099854).
Almost surely, 2100316314199707 is an apocalyptic number.
100316314199707 is a deficient number, since it is larger than the sum of its proper divisors (1).
100316314199707 is an equidigital number, since it uses as much as digits as its factorization.
100316314199707 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 857304, while the sum is 52.
The spelling of 100316314199707 in words is "one hundred trillion, three hundred sixteen billion, three hundred fourteen million, one hundred ninety-nine thousand, seven hundred seven".
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