Base | Representation |
---|---|
bin | 11101001100101001100… |
… | …01101111000000000001 |
3 | 10112220111100220102102121 |
4 | 32212110301233000001 |
5 | 112414100200224010 |
6 | 2044512520044241 |
7 | 132323545405231 |
oct | 16462461570001 |
9 | 3486440812377 |
10 | 1003223445505 |
11 | 357512532246 |
12 | 142521603681 |
13 | 737b0055b48 |
14 | 367b05b5cc1 |
15 | 1b1697463da |
hex | e994c6f001 |
1003223445505 has 16 divisors (see below), whose sum is σ = 1218251024640. Its totient is φ = 793002849408.
The previous prime is 1003223445431. The next prime is 1003223445527. The reversal of 1003223445505 is 5055443223001.
It is a cyclic number.
It is not a de Polignac number, because 1003223445505 - 211 = 1003223443457 is a prime.
It is a super-2 number, since 2×10032234455052 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 158907 + ... + 1425376.
It is an arithmetic number, because the mean of its divisors is an integer number (76140689040).
Almost surely, 21003223445505 is an apocalyptic number.
It is an amenable number.
1003223445505 is a deficient number, since it is larger than the sum of its proper divisors (215027579135).
1003223445505 is a wasteful number, since it uses less digits than its factorization.
1003223445505 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1585800.
The product of its (nonzero) digits is 72000, while the sum is 34.
Adding to 1003223445505 its reverse (5055443223001), we get a palindrome (6058666668506).
The spelling of 1003223445505 in words is "one trillion, three billion, two hundred twenty-three million, four hundred forty-five thousand, five hundred five".
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