Base | Representation |
---|---|
bin | 101110101101110111… |
… | …0011011011101111101 |
3 | 100120221200200211200011 |
4 | 1131123232123131331 |
5 | 3120430211124342 |
6 | 114030545103221 |
7 | 10151046444643 |
oct | 1353356333575 |
9 | 316850624604 |
10 | 100323145597 |
11 | 39601889184 |
12 | 1753a027b11 |
13 | 95ca75265c |
14 | 4bd9d3b193 |
15 | 29227bb717 |
hex | 175bb9b77d |
100323145597 has 2 divisors, whose sum is σ = 100323145598. Its totient is φ = 100323145596.
The previous prime is 100323145589. The next prime is 100323145603. The reversal of 100323145597 is 795541323001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 79498058116 + 20825087481 = 281954^2 + 144309^2 .
It is an emirp because it is prime and its reverse (795541323001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 100323145597 - 23 = 100323145589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100323145397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50161572798 + 50161572799.
It is an arithmetic number, because the mean of its divisors is an integer number (50161572799).
Almost surely, 2100323145597 is an apocalyptic number.
It is an amenable number.
100323145597 is a deficient number, since it is larger than the sum of its proper divisors (1).
100323145597 is an equidigital number, since it uses as much as digits as its factorization.
100323145597 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 113400, while the sum is 40.
Adding to 100323145597 its reverse (795541323001), we get a palindrome (895864468598).
The spelling of 100323145597 in words is "one hundred billion, three hundred twenty-three million, one hundred forty-five thousand, five hundred ninety-seven".
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