Base | Representation |
---|---|
bin | 101110101101111000… |
… | …1110001010010111001 |
3 | 100120221202100100002112 |
4 | 1131123301301102321 |
5 | 3120430422141213 |
6 | 114031015542105 |
7 | 10151060053256 |
oct | 1353361612271 |
9 | 316852310075 |
10 | 100324021433 |
11 | 39602327209 |
12 | 1753a38a935 |
13 | 95ca99b1bc |
14 | 4bda0c842d |
15 | 29228e0ea8 |
hex | 175bc714b9 |
100324021433 has 2 divisors, whose sum is σ = 100324021434. Its totient is φ = 100324021432.
The previous prime is 100324021417. The next prime is 100324021451. The reversal of 100324021433 is 334120423001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 58086784144 + 42237237289 = 241012^2 + 205517^2 .
It is a cyclic number.
It is not a de Polignac number, because 100324021433 - 24 = 100324021417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 100324021399 and 100324021408.
It is not a weakly prime, because it can be changed into another prime (100324021403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50162010716 + 50162010717.
It is an arithmetic number, because the mean of its divisors is an integer number (50162010717).
Almost surely, 2100324021433 is an apocalyptic number.
It is an amenable number.
100324021433 is a deficient number, since it is larger than the sum of its proper divisors (1).
100324021433 is an equidigital number, since it uses as much as digits as its factorization.
100324021433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 100324021433 its reverse (334120423001), we get a palindrome (434444444434).
The spelling of 100324021433 in words is "one hundred billion, three hundred twenty-four million, twenty-one thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •