Search a number
-
+
1003251223969 is a prime number
BaseRepresentation
bin11101001100101100110…
…11101100110110100001
310112220120022011201022121
432212112123230312201
5112414124303131334
62044515351304241
7132324333462061
oct16462633546641
93486508151277
101003251223969
11357527185655
1214252a97b081
13737b5a308c7
14367b41673a1
151b16bdd1db4
hexe9966ecda1

1003251223969 has 2 divisors, whose sum is σ = 1003251223970. Its totient is φ = 1003251223968.

The previous prime is 1003251223967. The next prime is 1003251224021. The reversal of 1003251223969 is 9693221523001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 981446862400 + 21804361569 = 990680^2 + 147663^2 .

It is a cyclic number.

It is not a de Polignac number, because 1003251223969 - 21 = 1003251223967 is a prime.

It is a super-2 number, since 2×10032512239692 (a number of 25 digits) contains 22 as substring.

Together with 1003251223967, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1003251223967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501625611984 + 501625611985.

It is an arithmetic number, because the mean of its divisors is an integer number (501625611985).

Almost surely, 21003251223969 is an apocalyptic number.

It is an amenable number.

1003251223969 is a deficient number, since it is larger than the sum of its proper divisors (1).

1003251223969 is an equidigital number, since it uses as much as digits as its factorization.

1003251223969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 174960, while the sum is 43.

The spelling of 1003251223969 in words is "one trillion, three billion, two hundred fifty-one million, two hundred twenty-three thousand, nine hundred sixty-nine".