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10033001133 = 33344333711
BaseRepresentation
bin10010101100000001…
…10111001010101101
3221220012212021011120
421112000313022231
5131021422014013
64335322011153
7503425050111
oct112600671255
927805767146
1010033001133
114289405281
121b40046ab9
13c3b7a347c
146b26b3741
153dac2b123
hex2560372ad

10033001133 has 4 divisors (see below), whose sum is σ = 13377334848. Its totient is φ = 6688667420.

The previous prime is 10033001131. The next prime is 10033001159. The reversal of 10033001133 is 33110033001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10033001133 - 21 = 10033001131 is a prime.

It is a super-2 number, since 2×100330011332 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10033001131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1672166853 + ... + 1672166858.

It is an arithmetic number, because the mean of its divisors is an integer number (3344333712).

Almost surely, 210033001133 is an apocalyptic number.

It is an amenable number.

10033001133 is a deficient number, since it is larger than the sum of its proper divisors (3344333715).

10033001133 is an equidigital number, since it uses as much as digits as its factorization.

10033001133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3344333714.

The product of its (nonzero) digits is 81, while the sum is 15.

Adding to 10033001133 its reverse (33110033001), we get a palindrome (43143034134).

The spelling of 10033001133 in words is "ten billion, thirty-three million, one thousand, one hundred thirty-three".

Divisors: 1 3 3344333711 10033001133