10033004011341 has 4 divisors (see below), whose sum is σ = 13377338681792. Its totient is φ = 6688669340892.

The previous prime is 10033004011337. The next prime is 10033004011379. The reversal of 10033004011341 is 14311040033001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10033004011341 - 2² = 10033004011337 is a prime.

It is a super-2 number, since 2×10033004011341² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10033004011841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1672167335221 + ... + 1672167335226.

It is an arithmetic number, because the mean of its divisors is an integer number (3344334670448).

Almost surely, 2^{10033004011341} is an apocalyptic number.

It is an amenable number.

10033004011341 is a deficient number, since it is larger than the sum of its proper divisors (3344334670451).

10033004011341 is an equidigital number, since it uses as much as digits as its factorization.

10033004011341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3344334670450.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 10033004011341 its reverse (14311040033001), we get a palindrome (24344044044342).

The spelling of 10033004011341 in words is "ten trillion, thirty-three billion, four million, eleven thousand, three hundred forty-one".