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10033051011 = 33344350337
BaseRepresentation
bin10010101100000010…
…00011010110000011
3221220012221210120220
421112001003112003
5131021430113021
64335323034123
7503425345404
oct112601032603
927805853526
1010033051011
1142894397a5
121b4006b943
13c3b7c0099
146b26c79ab
153dac3acc6
hex256043583

10033051011 has 4 divisors (see below), whose sum is σ = 13377401352. Its totient is φ = 6688700672.

The previous prime is 10033050959. The next prime is 10033051043. The reversal of 10033051011 is 11015033001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10033051011 is a prime.

It is a super-2 number, since 2×100330510112 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (10033051111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1672175166 + ... + 1672175171.

It is an arithmetic number, because the mean of its divisors is an integer number (3344350338).

Almost surely, 210033051011 is an apocalyptic number.

10033051011 is a deficient number, since it is larger than the sum of its proper divisors (3344350341).

10033051011 is an equidigital number, since it uses as much as digits as its factorization.

10033051011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3344350340.

The product of its (nonzero) digits is 45, while the sum is 15.

Adding to 10033051011 its reverse (11015033001), we get a palindrome (21048084012).

The spelling of 10033051011 in words is "ten billion, thirty-three million, fifty-one thousand, eleven".

Divisors: 1 3 3344350337 10033051011