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10034133997 is a prime number
BaseRepresentation
bin10010101100001010…
…01011101111101101
3221220021222211011111
421112011023233231
5131022214241442
64335402152021
7503440505656
oct112605135755
927807884144
1010034133997
11428a009428
121b404b2611
13c3baabcc4
146b28ca52d
153dada1b17
hex25614bbed

10034133997 has 2 divisors, whose sum is σ = 10034133998. Its totient is φ = 10034133996.

The previous prime is 10034133973. The next prime is 10034134027. The reversal of 10034133997 is 79933143001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8627808996 + 1406325001 = 92886^2 + 37501^2 .

It is an emirp because it is prime and its reverse (79933143001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10034133997 - 27 = 10034133869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10034131997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5017066998 + 5017066999.

It is an arithmetic number, because the mean of its divisors is an integer number (5017066999).

Almost surely, 210034133997 is an apocalyptic number.

It is an amenable number.

10034133997 is a deficient number, since it is larger than the sum of its proper divisors (1).

10034133997 is an equidigital number, since it uses as much as digits as its factorization.

10034133997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 61236, while the sum is 40.

Adding to 10034133997 its reverse (79933143001), we get a palindrome (89967276998).

The spelling of 10034133997 in words is "ten billion, thirty-four million, one hundred thirty-three thousand, nine hundred ninety-seven".